Solving Exponential Equation 4^(x^2) * 2^(3x) = 4 A Step-by-Step Guide

In the realm of mathematics, exponential equations hold a significant place, often appearing in various applications ranging from compound interest calculations to population growth models. These equations involve variables in the exponents, requiring a specific set of techniques to solve them effectively. In this article, we will delve into a detailed approach to solving the exponential equation 4x223x=44^{x^2} \cdot 2^{3x} = 4, providing a step-by-step guide that not only leads to the solution but also enhances your understanding of the underlying principles.

Understanding Exponential Equations

Before we embark on solving the given equation, it's crucial to grasp the fundamental concepts of exponential equations. An exponential equation is an equation where the variable appears in the exponent. The key to solving these equations lies in manipulating them to a form where we can equate either the bases or the exponents. In our case, we have the equation 4x223x=44^{x^2} \cdot 2^{3x} = 4. Notice that the bases are 4 and 2, which are powers of 2. This observation is the cornerstone of our solution strategy.

Rewriting the Equation with a Common Base

Our first step involves expressing all the terms in the equation with the same base. Since 4 is a power of 2 (4=224 = 2^2), we can rewrite the equation as follows:

(22)x223x=22(2^2)^{x^2} \cdot 2^{3x} = 2^2

Using the power of a power rule, which states that (am)n=amn(a^m)^n = a^{mn}, we can simplify the left side of the equation:

22x223x=222^{2x^2} \cdot 2^{3x} = 2^2

Now, we apply the product of powers rule, which states that aman=am+na^m \cdot a^n = a^{m+n}. This allows us to combine the terms on the left side:

22x2+3x=222^{2x^2 + 3x} = 2^2

Equating the Exponents

With the bases now the same, we can equate the exponents. This is a fundamental property of exponential equations: if am=ana^m = a^n, then m=nm = n. Applying this to our equation, we get:

2x2+3x=22x^2 + 3x = 2

This transformation has converted our exponential equation into a quadratic equation, which we can solve using standard algebraic techniques.

Solving the Quadratic Equation

The quadratic equation we obtained is 2x2+3x=22x^2 + 3x = 2. To solve it, we first need to bring all the terms to one side, setting the equation equal to zero:

2x2+3x2=02x^2 + 3x - 2 = 0

Now, we can solve this quadratic equation using factoring, completing the square, or the quadratic formula. In this case, factoring is a straightforward approach. We look for two numbers that multiply to -4 (2 \cdot -2) and add up to 3. These numbers are 4 and -1. We rewrite the middle term using these numbers:

2x2+4xx2=02x^2 + 4x - x - 2 = 0

Next, we factor by grouping:

2x(x+2)1(x+2)=02x(x + 2) - 1(x + 2) = 0

(2x1)(x+2)=0(2x - 1)(x + 2) = 0

This gives us two possible solutions for x:

2x1=02x - 1 = 0 or x+2=0x + 2 = 0

Solving for x in each case:

x=12x = \frac{1}{2} or x=2x = -2

Therefore, the solutions to the quadratic equation, and consequently to the original exponential equation, are x=12x = \frac{1}{2} and x=2x = -2.

Verifying the Solutions

It's always a good practice to verify the solutions we obtain, especially in exponential and logarithmic equations. We plug each solution back into the original equation to ensure it holds true.

Checking x=12x = \frac{1}{2}

Substituting x=12x = \frac{1}{2} into the original equation 4x223x=44^{x^2} \cdot 2^{3x} = 4:

4(12)223(12)=44^{(\frac{1}{2})^2} \cdot 2^{3(\frac{1}{2})} = 4

414232=44^{\frac{1}{4}} \cdot 2^{\frac{3}{2}} = 4

(22)14232=4(2^2)^{\frac{1}{4}} \cdot 2^{\frac{3}{2}} = 4

212232=42^{\frac{1}{2}} \cdot 2^{\frac{3}{2}} = 4

212+32=42^{\frac{1}{2} + \frac{3}{2}} = 4

22=42^2 = 4

4=44 = 4

The equation holds true for x=12x = \frac{1}{2}.

Checking x=2x = -2

Substituting x=2x = -2 into the original equation:

4(2)223(2)=44^{(-2)^2} \cdot 2^{3(-2)} = 4

4426=44^4 \cdot 2^{-6} = 4

(22)426=4(2^2)^4 \cdot 2^{-6} = 4

2826=42^8 \cdot 2^{-6} = 4

286=42^{8 - 6} = 4

22=42^2 = 4

4=44 = 4

The equation also holds true for x = -2.

Conclusion

In conclusion, the solutions to the exponential equation 4x223x=44^{x^2} \cdot 2^{3x} = 4 are x=12x = \frac{1}{2} and x=2x = -2. We arrived at these solutions by first rewriting the equation with a common base, then equating the exponents to form a quadratic equation. Solving the quadratic equation yielded the two solutions, which we subsequently verified by substituting them back into the original equation.

This step-by-step approach not only solves the specific equation but also illustrates the general methodology for tackling exponential equations. The key takeaways are:

  1. Express all terms with a common base.
  2. Use exponent rules to simplify the equation.
  3. Equate the exponents to form an algebraic equation.
  4. Solve the resulting algebraic equation.
  5. Verify the solutions.

By mastering these techniques, you'll be well-equipped to solve a wide range of exponential equations, enhancing your mathematical prowess and problem-solving skills.

Exponential equations are a cornerstone of mathematical concepts, frequently encountered in various scientific and engineering disciplines. These equations, characterized by variables appearing in exponents, demand a unique set of problem-solving strategies. In this article, we embark on a comprehensive journey to unravel the intricacies of exponential equations, equipping you with the knowledge and skills to confidently tackle them. We will delve into the fundamental principles, explore various solution techniques, and provide illustrative examples to solidify your understanding.

Delving into the Fundamentals of Exponential Equations

At its core, an exponential equation is an equation where the variable resides in the exponent. The general form of an exponential equation can be expressed as:

af(x)=ba^{f(x)} = b

where:

  • a is the base (a positive real number not equal to 1)
  • f(x) is a function of the variable x (often a polynomial)
  • b is a constant.

The challenge in solving exponential equations stems from the variable's presence in the exponent. Our primary objective is to manipulate the equation into a form where we can either equate the bases or the exponents. This often involves leveraging the properties of exponents and logarithms. Understanding these properties is crucial for effective problem-solving.

Key Properties of Exponents

  • Product of powers: aman=am+na^m \cdot a^n = a^{m+n}
  • Quotient of powers: aman=amn\frac{a^m}{a^n} = a^{m-n}
  • Power of a power: (am)n=amn(a^m)^n = a^{mn}
  • Power of a product: (ab)n=anbn(ab)^n = a^n b^n
  • Power of a quotient: (ab)n=anbn(\frac{a}{b})^n = \frac{a^n}{b^n}
  • Zero exponent: a0=1a^0 = 1 (where a0a \neq 0)
  • Negative exponent: an=1ana^{-n} = \frac{1}{a^n}

These properties serve as the building blocks for simplifying and solving exponential equations. Let's explore the common techniques used to tackle these equations.

Unveiling the Techniques for Solving Exponential Equations

There are several methods for solving exponential equations, each tailored to specific equation structures. Here, we'll explore the most widely used techniques:

1. Equating the Bases

This technique is applicable when we can express both sides of the equation with the same base. If af(x)=ag(x)a^{f(x)} = a^{g(x)}, then we can conclude that f(x)=g(x)f(x) = g(x). This method is the most straightforward and efficient when applicable.

Example: Solve 2x+1=82^{x+1} = 8

Solution: We can rewrite 8 as 232^3, so the equation becomes 2x+1=232^{x+1} = 2^3. Equating the exponents, we get x+1=3x+1 = 3, which gives us x=2x=2.

2. Using Logarithms

Logarithms are the inverse functions of exponentials, making them indispensable tools for solving exponential equations. The fundamental property we use is:

If ax=ba^x = b, then loga(b)=xlog_a(b) = x

In practice, we often use the common logarithm (base 10) or the natural logarithm (base e) for convenience. Applying logarithms to both sides of the equation allows us to bring the variable down from the exponent.

Example: Solve 5x=125^x = 12

Solution: Taking the natural logarithm of both sides, we get ln(5x)=ln(12)ln(5^x) = ln(12). Using the power rule of logarithms, we have xln(5)=ln(12)x \cdot ln(5) = ln(12). Dividing both sides by ln(5)ln(5), we get x=ln(12)ln(5)1.544x = \frac{ln(12)}{ln(5)} \approx 1.544.

3. Substitution

In some cases, exponential equations can be simplified by using substitution. This is particularly useful when the equation contains expressions that can be treated as a single variable. Substitution can transform complex equations into more manageable forms.

Example: Solve 4x2x+18=04^x - 2^{x+1} - 8 = 0

Solution: Notice that 4x=(22)x=(2x)24^x = (2^2)^x = (2^x)^2. Let y=2xy = 2^x. The equation becomes y22y8=0y^2 - 2y - 8 = 0. Factoring, we get (y4)(y+2)=0(y-4)(y+2) = 0, so y=4y = 4 or y=2y = -2. Since 2x2^x cannot be negative, we discard y=2y=-2. For y=4y=4, we have 2x=42^x = 4, which gives us x=2x=2.

4. Graphical Methods

Graphical methods can be employed to approximate solutions to exponential equations. This involves graphing the functions on both sides of the equation and finding the points of intersection. While not providing exact solutions, graphical methods offer valuable insights and can be used to verify analytical solutions. Visualizing the equations can enhance understanding.

To effectively solve exponential equations, a systematic approach is essential. Here's a step-by-step guide:

  1. Simplify the equation: Use the properties of exponents to simplify both sides of the equation.
  2. Isolate the exponential term: If possible, isolate the term containing the variable in the exponent.
  3. Express with a common base: If possible, express both sides of the equation with the same base.
  4. Equate the exponents: If the bases are the same, equate the exponents and solve the resulting equation.
  5. Apply logarithms: If a common base cannot be found, apply logarithms to both sides of the equation.
  6. Solve for the variable: Solve the resulting equation (linear, quadratic, etc.) for the variable.
  7. Verify the solutions: Check the solutions by substituting them back into the original equation.

Real-World Applications of Exponential Equations

Exponential equations are not mere mathematical constructs; they have profound applications in various real-world scenarios:

  • Compound interest: Exponential equations model the growth of investments with compound interest.
  • Population growth: Exponential functions describe the growth of populations over time.
  • Radioactive decay: Exponential decay models the decay of radioactive substances.
  • Chemical reactions: Exponential equations describe the rates of certain chemical reactions.
  • Spread of diseases: Exponential functions can model the spread of infectious diseases.

Conclusion: Mastering the Art of Solving Exponential Equations

Solving exponential equations is a fundamental skill in mathematics with wide-ranging applications. By mastering the techniques outlined in this article, you'll be well-equipped to tackle these equations confidently. Remember to:

  • Understand the properties of exponents and logarithms.
  • Choose the appropriate solution technique.
  • Follow a systematic approach.
  • Verify your solutions.

With practice and perseverance, you'll unlock the power of exponential equations and their ability to model and explain the world around us. Embrace the challenge, and you'll discover the beauty and versatility of these mathematical tools.

Exponential equations, a fascinating area within mathematics, are characterized by variables nestled within exponents. Their significance reverberates across diverse fields like physics, engineering, finance, and computer science, where they model phenomena from population growth to radioactive decay. Understanding and solving exponential equations is therefore a vital skill for any aspiring mathematician, scientist, or engineer. This article aims to unravel the intricacies of exponential equations, providing a comprehensive guide to various solution techniques, accompanied by illustrative examples.

Laying the Foundation: Understanding Exponential Equations

An exponential equation, in its essence, is an equation where the variable resides in the exponent. A typical representation of an exponential equation is:

af(x)=ca^{f(x)} = c

Where:

  • a is the base, a positive real number not equal to 1.
  • f(x) is a function of the variable x, often a linear or quadratic expression.
  • c is a constant.

Solving these equations necessitates a distinct toolkit of techniques, primarily focusing on manipulating the equation to isolate the variable. This often involves leveraging the properties of exponents and, crucially, the properties of logarithms. A firm grasp of these properties is the bedrock of successful problem-solving.

Essential Properties of Exponents

  • Product of powers: aman=am+na^m \cdot a^n = a^{m+n}
  • Quotient of powers: aman=amn\frac{a^m}{a^n} = a^{m-n}
  • Power of a power: (am)n=amn(a^m)^n = a^{mn}
  • Power of a product: (ab)n=anbn(ab)^n = a^n b^n
  • Power of a quotient: (ab)n=anbn(\frac{a}{b})^n = \frac{a^n}{b^n}
  • Zero exponent: a0=1a^0 = 1, where a0a \neq 0
  • Negative exponent: an=1ana^{-n} = \frac{1}{a^n}

These properties serve as the foundation for simplifying and manipulating exponential equations. Now, let's explore the core techniques employed to solve these equations.

Unlocking the Solution: Techniques for Solving Exponential Equations

Several techniques exist for tackling exponential equations, each suited to different equation structures and complexities. Here, we will dissect the most prevalent methods:

1. Equating the Bases: A Direct Approach

The method of equating bases shines when both sides of the equation can be expressed with a common base. This allows us to directly equate the exponents and solve the resulting algebraic equation. If af(x)=ag(x)a^{f(x)} = a^{g(x)}, then we can confidently deduce that f(x)=g(x)f(x) = g(x). This method provides the most elegant solution when applicable.

Example: Solve 32x1=273^{2x-1} = 27

Solution: We can express 27 as 333^3, transforming the equation to 32x1=333^{2x-1} = 3^3. Equating the exponents, we get 2x1=32x-1 = 3. Solving for x, we find x=2x=2.

2. The Power of Logarithms: A Versatile Tool

Logarithms, the inverse functions of exponentials, are indispensable for solving exponential equations, especially when expressing both sides with a common base proves challenging. The fundamental property underpinning this technique is:

If ax=ba^x = b, then loga(b)=xlog_a(b) = x

In practice, we commonly employ the common logarithm (base 10) or the natural logarithm (base e) for convenience. Applying logarithms to both sides of the equation allows us to extract the variable from the exponent, transforming the problem into a solvable algebraic equation. Logarithms unlock solutions that would otherwise remain inaccessible.

Example: Solve 7x=207^x = 20

Solution: Taking the natural logarithm of both sides yields ln(7x)=ln(20)ln(7^x) = ln(20). Using the power rule of logarithms, we get xln(7)=ln(20)x \cdot ln(7) = ln(20). Dividing both sides by ln(7)ln(7), we find x=ln(20)ln(7)1.539x = \frac{ln(20)}{ln(7)} \approx 1.539.

3. Substitution: Taming Complexity

Certain exponential equations can be simplified through strategic substitution. This is particularly effective when the equation harbors expressions that can be treated as a single variable, thereby reducing the equation's complexity. Substitution transforms intricate equations into manageable forms.

Example: Solve 9x43x+3=09^x - 4 \cdot 3^x + 3 = 0

Solution: Recognizing that 9x=(3x)29^x = (3^x)^2, we let y=3xy = 3^x. The equation transforms into y24y+3=0y^2 - 4y + 3 = 0. Factoring, we get (y3)(y1)=0(y-3)(y-1) = 0, yielding y=3y=3 or y=1y=1. Substituting back, we have 3x=33^x = 3, which gives x=1x=1, and 3x=13^x = 1, which gives x=0x=0.

4. Graphical Methods: Visualizing Solutions

Graphical methods offer a visual approach to approximating solutions to exponential equations. This involves graphing the functions on both sides of the equation and identifying their points of intersection. While not providing precise solutions, graphical methods provide valuable insights and serve as a verification tool for analytical solutions. Visual representation enhances comprehension.

A Step-by-Step Guide: Solving Exponential Equations Effectively

Solving exponential equations effectively demands a systematic approach. Here's a step-by-step guide to navigate the process:

  1. Simplify: Use the properties of exponents to simplify both sides of the equation.
  2. Isolate: Isolate the exponential term, if possible.
  3. Common Base: Express both sides with a common base, if feasible.
  4. Equate Exponents: If a common base is achieved, equate the exponents and solve the resulting equation.
  5. Apply Logarithms: If a common base is elusive, apply logarithms to both sides.
  6. Solve: Solve the resulting equation (linear, quadratic, etc.).
  7. Verify: Check the solutions by substituting them back into the original equation.

The Far-Reaching Applications of Exponential Equations

Exponential equations are not confined to the realm of pure mathematics; they are powerful tools for modeling real-world phenomena:

  • Finance: Compound interest calculations rely heavily on exponential equations.
  • Biology: Population growth and decay are modeled using exponential functions.
  • Physics: Radioactive decay and other physical processes are described by exponential equations.
  • Engineering: Exponential functions appear in circuit analysis and signal processing.
  • Computer Science: Algorithms and data structures often exhibit exponential behavior.

Concluding Thoughts: Mastering the Art of Exponential Equations

Solving exponential equations is a fundamental skill in mathematics, with applications spanning numerous disciplines. By mastering the techniques outlined in this article, you'll be well-prepared to tackle these equations with confidence. Key takeaways include:

  • A solid understanding of exponent and logarithm properties.
  • The ability to select the appropriate solution technique.
  • A systematic approach to problem-solving.
  • The importance of verifying solutions.

With consistent practice and a commitment to understanding the underlying principles, you'll unlock the power of exponential equations and their ability to model and explain the complexities of the world around us. Embrace the challenge, and you'll discover the beauty and versatility of these mathematical tools.